Question

$see \: the \: attachment \: \\ \\ when \: we \: release \: the \: block \: from \: 2m \: above \: the \: spring \: hat \: will \: be \: the \: kinetc \: friction.mass \: of \: the \: block \: is \: 2kg. \\ \\ details \: given \: in \: the \: figure$
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Answer 1

$hey \: there \: is \: a \: slight \: error \: \\ we \: have \: t \: find \: the \: k \: of \: spring \: \\ here \: kinetic \: energy \: is \: zero \\ \\ work \: done \: by \: all \: the \: forces = total \: kinetic \: energy \\ \\ w.spr + w.gravity = 0 \\ - \frac{1}{2}k( { \frac{50}{100}}^{2}) \: + mg \frac{250}{100} = 0 \\ - \frac{1}{2} k \frac{1}{4} = 2 \times 10 \times 2.5 \\ k = 8 \times 50 = 400n {m}^{ - 1} \\ \\ thank \: you$