Question

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(0,0)(0,0)(6,0)\put(2,0){\framebox(2,2.5){\sf 2kg}}\put(2,1){\vector(-1,0){2}}\multiput(4,0.5)(0,1){2}{\put(0,0){\vector(1,0){2}}}\put(1,1.2){\sf 20N}\put(5,0.2){\sf 12N}\put(5,1.7){\sf 10N}\multiput(0.2,0)(0.2,0){30}{\put(0,0){\line(-1,-1){0.5}}}\end{picture}$
$\huge{\sf Figure\uparrow}$

$\huge{\underline{\sf Question\:for\:Physicians}}$

What will be the net acceleration of a given block of mass 2kg kept on a smooth surface ?

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Answer 1

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(0,0)(0,0)(6,0)\put(2,0){\framebox(2,2.5){\sf 2kg}}\put(2,1){\vector(-1,0){2}}\multiput(4,0.5)(0,1){2}{\put(0,0){\vector(1,0){2}}}\put(1,1.2){\sf 20N}\put(5,0.2){\sf 12N}\put(5,1.7){\sf 10N}\multiput(0.2,0)(0.2,0){30}{\put(0,0){\line(-1,-1){0.5}}}\end{picture}$

$\huge{\sf Figure\uparrow}$

Given, the mass of the block is 2 kg.

To find, the net acceleration of the block kept on the smooth surface.

We know that, force (F) equals the product of mass (m) and acceleration (a).

Hence, the formula will be F = ma.

We also know that, the SI unit of force is Newton, which is denoted as N.

Net forceﾠ= [(12 + 10) - 20] N

ﾠﾠﾠﾠﾠﾠﾠﾠﾠ= (22 - 20) N

ﾠﾠﾠﾠﾠﾠﾠﾠﾠ= 2 N

By putting the respected value in the stated formula, we get

$\normalsize {\tt {~~~~~~~~~~~~~2 ~N ~= ~2~ kg ~ \times a}}$

$\normalsize {\tt {\longrightarrow~~~~~ \frac{2~ N}{2~kg} = a }}$

$\normalsize {\tt {\longrightarrow 1~N/kg = a}}$

$\normalsize {\tt {\longrightarrow 1~m/{s}^{2} = a}}$

Answer:

The net acceleration of the given block of mass 2 kg kept on the smooth surface is 1 m/s^2 .

Answer 2

${EXPLANATION}$

Solution :-

If we sèe the picture

There is a block of mass 2kg and there are different forces acting on them

First we find the net force acting on the object

Conecpt to find the net force :-

Net force is nothing but Sum of algebraic forces acting on the body is called net force

☆ If the object moves in straght line and same direction net force is sum of the forces

☆If the object moves in straight line and opposite direction net force is the difference of the forces

_________________________

So, the force acting on the body is

F = (10N + 12N )- 20N

F = 22N - 20N

${\boxed{F = 2N}}$

• So, force acting on the body is 2N
• Mass of the body is 2kg

We know that ,

Force = mass × acceleration

F = m× a

2 = 2 × a

${\boxed{a = 1 m/s^2 }}$

So, the Acceleration of the body is 1m/s²