Question

$\sf{4 cos20^\circ-\sqrt{3}cot20^\circ }$ =? ​

Answer 1

L.H.S=sin20∘1(2sin40∘−2sin60∘cos20∘)

L.H.S=sin20∘1[(2sin40∘−(sin80∘+sin40∘)]

L.H.S=sin20∘1[sin40∘−sin80∘]

L.H.S=sin20∘1[2sin(−20∘)cos60∘]=−1

Answer 2

Answer:

4*cos(20) - √3cot(20)

= 4*0.939692621 - √3*2.74747742

= 3.75877048 - 4.75877048

= -1.