Question

$\sf{@BrainlyNavodayan786 \: Help \: me \: please!}$
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Answer 1

A)

Given :

In ∆ ABC , DE parallel to BC

• AD = 3 cm
• DB = 2 cm
• EC = 4 cm

What To Find :

Length of AC

Solution :

According to Basic proportionality theorem.

$\large\begin{gathered} {\underline{\boxed{ \rm {\red{ \frac{AD }{DB} \: = \: \frac{AE }{EC} }}}}}\end{gathered}$

Substuting the values

$\begin{cases}{\large\bf{{\purple{ \longrightarrow}}}} \rm \: \frac{3 }{2} \: = \: \frac{AE }{4} \\ \\ {\large\bf{{\purple{ \longrightarrow}}}} \rm \: AE \: = \: \frac{4 \: \times \: 3}{2} \\ \\{\large\bf{{\purple{ \longrightarrow}}}} \rm \: AE \: = \: \cancel\frac{12}{2} \\ \\ {\large\bf{{\purple{ \longrightarrow}}}} \rm \: AE \: = \: 6 \: cm \end{cases}$

AC = AE + EC

• AE = 6 CM
• EC = 4 CM

Now , adding the values

AC = 6 cm + 4 cm

AC = 10 cm

$\large\mid \ {\bf \underline{{{\color{orange}{AC = 10 \: cm}}}}} \mid$

Answer 2

A)

Given :

In ∆ ABC , DE parallel to BC

AD = 3 cm

DB = 2 cm

EC = 4 cm

What To Find :

Length of AC

Solution :

According to Basic proportionality theorem.

Substuting the values

AC = AE + EC

AE = 6 CM

EC = 4 CM

Now , adding the values

AC = 6 cm + 4 cm

AC = 10 cm

Answer:

Step-by-step explanation: