Math, asked by sia1234567, 1 month ago


  \sf\bigstar \: standard - 9th \\   \sf\bigstar \: chemistry \: question
  \underline{\underline \bold \red{balance \: the \: following \: equations : - }}
 \bold{Cu+H_2SO_4  \tiny[conc.]  }\bold {\Rightarrow CuSO_4 + H_2O + SO_2 }
 \bold{S+H_2SO_4 \tiny[conc.] }  \bold{\Rightarrow \: SO_2 + H_2O}
 \bold{HNO_3  \Rightarrow \: H_2O +NO_2 + O_2 }
 \bold{Pb(NO_3)_2 + NaCl  \Rightarrow \: NaNO_3 + PbCl_2}
 \bold{Fe+ HCl  \Rightarrow \: FeCl_2 +H_2 }
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Answers

Answered by SavageBlast
51

 \large \underline{\underline \bold \blue{Balancing \: the \: following \: equations : - }}

1)  \bold{Cu+H_2SO_4 \tiny[conc.] }\bold {\Rightarrow CuSO_4 + H_2O + SO_2 }

\sf \implies {\red{Cu+2H_2SO_4 {\Rightarrow CuSO_4 +2 H_2O + SO_2 }}}

  • Single Displacement Reaction

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

2)  \bold{S+H_2SO_4 \tiny[conc.] } \bold{\Rightarrow \: SO_2 + H_2O}

\sf \implies {\red{S+2H_2SO_4 {\Rightarrow \: 3SO_2 + 2H_2O}}}

  • Single Displacement Reaction

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

3)  \bold{HNO_3 \Rightarrow \: H_2O +NO_2 + O_2 }

\sf\implies {\red{4HNO_3 \Rightarrow \: 2H_2O +4NO_2 + O_2 }}

  • Decomposition Reaction

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

4)  \bold{Pb(NO_3)_2 + NaCl \Rightarrow \: NaNO_3 + PbCl_2}

\sf \implies {\red{Pb(NO_3)_2 + 2NaCl \Rightarrow \: 2NaNO_3 + PbCl_2}}

  • Double Displacement Reaction

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

5)  \bold{Fe+ HCl \Rightarrow \: FeCl_2 +H_2 }

\sf \implies {\red{Fe+ 2HCl \Rightarrow \: FeCl_2 +H_2 }}

  • Single Displacement Reaction

━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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