Question

$\sf \blue{Question : }$
•Which are the four identities?
•Compute this using an identity.
$\sf\implies346^{2}\\\sf\implies 453 ^{2} =$
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Thank you ✌✨​

Answer 1

Answer:

1. the four identities are -

a2-b2 =( a+b ) ( A-b )

(a+b)2 4( a2+2ab+b2)

x+a x+b= ( x2 + a+b ) x + ab

( a-b)2 = a2-2ab -b2

for this question u have to used a2-b2 identity

for this identity u have to find a no which decreased to 346square and increases to

453square and then apply identity (a+b) ( a-b) . u answar comes .

hope it helps you

Answer 2

Answer:

• The four identities are

$\large\underline{\sf{ {(a+b) }^{2} = {a}^{2} + 2ab + {b}^{2} }}$

$\large\underline{\sf{ {(a - b)}^{2} = {a}^{2} -2ab + {b}^{2} }}$

$\large\underline{\sf{ {a}^{2} - {b}^{2} = (a +b )(a - b) }}$

$\large\underline{\sf{(x + a)(x + b) = {x}^{2} + (a + b)x + ab }}$

• 126736

Step-by-step explanation:

$\large\underline{\sf{( {356)}^{2} = (300 + 56 {)}^{2} }}$

$\large\underline{\sf{ {300}^{2} + 2 \times 300 \times 56 + {56}^{2} }}$

$\large\underline{\sf{90000 +33600 + 3136 }}$

$\implies126736$

$\large\underline{\sf{ {453}^{2} = {500}^{2} - 2 \times 500 \times 47 + {47}^{2} }}$

$\large\underline{\sf{250000 - 47000 + 2209}}$

$\implies205209$