Question

$\sf {By \: using \: the \: concept \: of \: equation \: of \: a \: line,}$
$\sf { prove \: that \: the \: three \: points \: (3 , 0), (-2 , -2), \: }$
$\sf{ \: and \: (8 , 2) are \: collinear.}$


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Answer 1

Answer:

here's ur ans dear frnd

Step-by-step explanation:

In order to show that the points (3,0), (-2, -2) and (8, 2) are collinear, it suffices to show that the line passing through point (3,0) and (-2, -2) also passes through point (8, 2).

The equation of the line passing through points (3,0), (-2, -2) is

(y−0)=

(−2−3)

(−2−0)

(x−3)

y=

−5

−2

(x−3)

5y=2x−6

i.e. 2x−5y=6

It is observed that at x = 8 and y = 2,

L.H.S. = 2×8−5×2=16−10=6 = R.H.S.

Therefore, the line passing through points (3, 0) and (-2, -2) also passes through point (8, 2).

Hence, points (3,0), (-2, -2) and (8, 2) are collinear.

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Answer 2

Answer:

Ur ans yaar

I hope you have got the ans