Math, asked by Anonymous, 1 year ago

\sf{Chapter:} Inverse Trigonometric Functions

\sf{Class:} 12th​

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afdwl: what is the answer of the first one ?
Anonymous: I don't know :(

Answers

Answered by swarnali22
11
1. plug in the value .

2. plug in the value .

3. factorise , then cancel and finally plug in the value .

4. rationalise , factorise and plug in the value .

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thanks ..
Attachments:
Answered by Anonymous
14

1)4-2-2/8-7=>0/1=>0

3)4-4/8-8=0

L HOSPITAL RULE

X^2-2X+X-2/(x-2)(x^2+4)

X(x-2)+1(x-2)/(x-2)(x^2+4)

(x-2)(x+1)/(x-2)(x^2+4)

X+1/x^2+4

2+1/4+4

3/8

4)16-16/root4+5 - 3

0/root9 - 3

0/0

L hospital rule

.... Step by step do it

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