Question

${ \sf{ \color{maroon}{Question:−}}}$


The sum of two rational number is -2 if one
of the number is 10/3 the other number is?

___
Spam = Pata nhi Tumhare id Ke sath kya Hoga -_-" ​

Answer 1

Answer:

Hey mate,

Answer to your question is ──

Given,

Sum = -2

one number = 10/3

other number = ?

To find,

Other number = X

then,

X + 10/3 = -2

X = -2 -10/3

X = -2/1 -10/3

X = (-6) +(-10) /3 ( by taking lCM of 1 and 3)

x = -16/3

Hope it helps you.

With regards, Divya.

Bye Rollerqueen♡

Answer 2

Answer:

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{maroon}{Given:}}}}}}}\end{gathered}$

• $\red\bigstar$ The sum of two rational number is -2.
• $\red\bigstar$ One of the number is 10/3.

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{maroon}{To Find:}}}}}}}\end{gathered}$

• $\red\bigstar$ Other Number

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{maroon}{Solution:}}}}}}}\end{gathered}$

${\dag{\underline{\sf{Let \: the,}}}}$

• $\green\star$ Other number be = x
• $\green\star$ First number = 10/3

$\dag{\underline{\sf{According \: to \: the \: question}}}$

${: \implies{\sf{\dfrac{10}{3} + x = -2}}}$

${: \implies{\sf{ x = -2 - \dfrac{10}{3}}}}$

${: \implies{\sf{ x = - \dfrac{2}{1} - \dfrac{10}{3}}}}$

${: \implies{\sf{ x = - \dfrac{6 + 10}{3}}}}\qquad {\big\{{ - + - = + \big\}}}$

${: \implies{\sf{ x = - \dfrac{16}{3}}}}$

$\dag{\underline{\boxed{\bf{\red{x= - \dfrac{16}{3}}}}}}$

$\therefore{\underline{\sf{Hence \: the \: other \: number \: is \: \dfrac{16}{3}}}}$

$\begin{gathered}\end{gathered}$

$\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline{\color{maroon}{Verification:}}}}}}}\end{gathered}$

${: \implies{\sf{\dfrac{10}{3} + x = -2}}}$

• Substituting the values of x

${: \implies{\sf\bigg({\dfrac{10}{3}\bigg) +\bigg( - \dfrac{16}{3}\bigg) = -2}}}$

${: \implies{\sf\bigg({\dfrac{10}{3} - \dfrac{16}{3}\bigg) = -2}}}$

${: \implies{\sf\bigg({\dfrac{10 - 16}{3} \bigg) = -2}}}$

${: \implies{\sf\bigg({ - \dfrac{6}{3} \bigg) = -2}}}$

${: \implies{\sf{\cancel{ - \dfrac{6}{3}}= -2}}}$

${: \implies{\sf{ - 2} = -2}}$

$\dag{\underline{\boxed{\bf{\red{ LHS=RHS }}}}}$

$\therefore{\underline{\sf{Hence \: Verified}} \: \checkmark}$