Question

$\sf\:  \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6} = 5$​

Answer 1

Answer:

=$\frac{2(3m-1)-(2m+2)}{6} = 5$

=$\frac{6m-2-2m-2}{6} = 5$

=$4m-4 = 5X6$

=$4(m-1) = 5 X 6$

=$m-1 = \frac{30}{4}$

=$m=\frac{15}{2} + 1$

=$m=\frac{17}{2}$

∴$m=8\frac{1}{2}$

Answer 2

To Find :-

• Value of m

Solution:-

Given that,

• $\sf\:  \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6} = 5$

Here,

$\sf:\implies \: \dfrac{3m - 1}{3} - \dfrac{2m + 2}{6} = 5$

$\sf :\implies \:\dfrac{2(3m - 1) - (2m + 2)}{6} = 5$

$\sf :\implies \:\dfrac{6m - 2 - 2m - 2}{6} = 5$

$\sf :\implies \:\dfrac{4m - 4}{6} = 5$

$\sf:\implies \:4m - 4 = 30$

$\sf :\implies \:4m = 34$

$\bf:\implies \:m = \dfrac{17}{2}$

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Verification:-

On substituting the value of m, we get

$\sf\:  \longrightarrow \: \dfrac{3 \times \dfrac{17}{2} - 1}{3} - \dfrac{2 \times \dfrac{17}{2} + 2}{6}$

$\sf \:  \longrightarrow \:\dfrac{51 - 2}{6} - \dfrac{17 + 2}{6}$

$\sf\:  \longrightarrow \:\dfrac{49}{6} - \dfrac{19}{6}$

$\sf\:  \longrightarrow \:\dfrac{49 - 19}{6}$

$\sf \:  \longrightarrow \:\dfrac{30}{6}$

$\sf \:  \longrightarrow \:5$

$\bf\implies LHS = RHS$

Verified

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