Question

$\sf \dfrac{3x}{2} + \dfrac{5}{8} = \dfrac{2}{5} \: \\ \\ \textmd {find \: x}$
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Answer 1

Answer

$\sf \dfrac{3x}{2} + \dfrac{5}{8} = \dfrac{2}{5} \: \\ \\ \textmd {find \: x}$

=⟩ 24x+10/16 = 2/5

=⟩ Cross multiplying the terms, we get :-

=⟩ 120x + 50 = 32

=⟩ 120x = 32- 50

=⟩ 120x = -18

=⟩ x = -18/120

=⟩ x = -3/20

Answer 2

Given,

$: \implies \frac{3x}{2} + \frac{5}{8} = \frac{2}{5}$

To Find,

• The Value Of X .

Solution,

$: \implies \frac{3x}{2} + \frac{5}{8} = \frac{2}{5} \\ \\ : \implies \frac{3x}{2} + \frac{5}{8} = \frac{2}{5} \\ \\: \implies \frac{3x}{2} = \frac{2}{5} - \frac{5}{8} \\ \\ : \implies \frac{3x}{2} = \frac{8 \times 2 - 5 \times 5}{40} \\ \\ : \implies \frac{3x}{2} = \frac{16 - 25}{40} \\ \\ : \implies \frac{3x}{2} = \frac{ - 9}{40} \\ \\ : \implies x = \frac{ - 9}{40} \times \frac{2}{3} \\ \\ : \implies \color{red} \boxed{x = \frac{ - 3}{20} }$

Required Answer,

$: \implies \color{red} \boxed{x = \frac{ - 3}{20} }$