Question

$\sf\dfrac{cos 30\degree + sin60\degree }{1+sin30\degree +cos60\degree}=$​

Answer 1

$\underline{\underline{\sf{\color{magenta}{SOLUTION:-}}}}$

$\sf{\dfrac{cos30^\circ+sin60^\circ}{1+sin30^\circ+cos60^\circ} }$

$\sf{=\dfrac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2} }{1+\frac{1}{2}+\frac{1}{2}} }$

$\sf{=\dfrac{\frac{2\sqrt{3}}{2} }{1+1} }$

$\sf{=\dfrac{\sqrt{3}}{2} }$

Therefore, the answer is √3/2.

$\underline{\underline{\sf{\color{magenta}{FORMULAE\ USED:-}}}}$

$\bullet\ \sf{cos30^\circ=sin60^\circ=\dfrac{\sqrt{3}}{2} }$

$\bullet\ \sf{sin30^\circ=cos60^\circ=\dfrac{1}{2}}$