Question

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A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Given the magnitude and direction of the acceleration of the body.

➪Explain~

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Answer 1

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Answer 2

Answer:

Magnitude of Resultant Force= 10 N

Direction of Resultant Force= x-y plane

Acceleration of the body= 2 m/s²

Explanation:

Given:-

    Mass of body, m = 5 kg

     Forces, F₁ = 8 N

                  F₂ = 6 N    ( Each perpendicular to another )

Let the acceleration of the body be 'a' and resultant force be 'Fr'.

Now, we know by formula that resultant force is given by:

        |F|  = √F₁² + F₂² _____(1)

Putting the given values in eq (1), we get:

        |Fr| = √8² + 6²

        |Fr| = √ 64 + 36

        |Fr|= √100

        |Fr| = 10 N

Now we find the acceleration of the body.

We know by formula that:

    Acceleration, a = F/m

Putting the given values in the above formula, we get:

                 a = 10 N/ 5  kg

                 a = 2 m/s²

Therefore, the magnitude of the resultant force is 10 N and its direction is in x-y plane. Also, the acceleration of the body is 2 m/s².

Hope it helps! ;-))