☞ ... Places A and B are 30 km apart and they are on a straight road . Hamid travels from A to B on bike . At the same time Joseph starts from B on bike , travels towards A . They meet each other after 20 minutes . If Joseph would have started from B at the same time but in the opposite direction ( instead of towards A ) Hamid would have caught him after 3 hours . Find the speed of Hamid and Joseph ... ?
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Solution
Let speed of Hamid = H km/hr
Let speed of Joseph = J. km/hr
Then when they travel in opposite direction
x=H×
3
1
30−x=J×
3
1
⇒30−H/3=J/3
⇒[J=90−H]...(i)
When same direction & meet at c
D=J×3
30+D=3H
[30+3J=3H]...(ii)
On solving eq
n
(i) & (ii) we get
[H = 50 km/br & J = 40 km/hr]
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