Question

$\sf {Find\:the\;mean\:of\:the\:Given\:data\:using\: any\:method}$

$\begin{gathered}\boxed{\begin{array}{c|c|c|c|c|c|c|c}\bf {Class\:interval:-} &\sf 10-10 &\sf 20-29 &\sf 30-39 &\sf 40-49 &\sf 50-59 &\sf 60-69 &\sf 70-79 \\&&&&&&&\\ \bf {Frequency:-} &\sf 5 &\sf 65 &\sf 222 &\sf 112 &\sf 53 &\sf 40 &\sf 3 \end {array}}\end{gathered}$

Construct a frequency table for your answer.

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Answer 1

To Find:-

• Find the mean of the data.

Solution:-

As we know that:-

• $\sf \: Mean = \dfrac { Sum \: of \: Class \: Interval } { Frequency }$

Here ,

• Sum of class interval is 19500

• Sun of frequency is 500

$\longrightarrow\sf \: Mean = \cancel\dfrac { 19500 } { 500 }$

$\longrightarrow\sf \: Mean = 39$

Hence ,

• Mean is 39

Answer 2

Answer:

Find\:the\;mean\:of\:the\:Given\:data\:using\: any\:method}[/tex]

$\begin{gathered}\boxed{\begin{array}{c|c|c|c|c|c|c|c}\bf {Class\:interval:-} &\sf 10-10 &\sf 20-29 &\sf 30-39 &\sf 40-49 &\sf 50-59 &\sf 60-69 &\sf 70-79 \\&&&&&&&\\ \bf {Frequency:-} &\sf 5 &\sf 65 &\sf 222 &\sf 112 &\sf 53 &\sf 40 &\sf 3 \end {array}}\end{gathered}$

Construct a frequency table for your answer.

Spam=strict action will be taken