Question

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ᴀ ʙᴏʏ ᴡᴀʟᴋɪɴɢ ᴀᴛ ᴀ sᴘᴇᴇᴅ ᴏғ 10ᴋᴍ/ʜʀ ʀᴇᴀᴄʜᴇs ʜɪs sᴄʜᴏᴏʟ 15 ᴍɪɴᴜᴛᴇs ʟᴀᴛᴇ ɴᴇxᴛ ᴛɪᴍᴇ ʜᴇ ɪɴᴄʀᴇᴀsᴇs ʜɪs sᴘᴇᴇᴅ ʙʏ 2 ᴋᴍ/ʜʀ,ʙᴜᴛ sᴛɪʟʟ,ʜᴇ ɪs ʟᴀᴛᴇ ʙʏ 5 ᴍɪɴᴜᴛᴇs ғɪɴᴅ ᴛʜᴇ ᴅɪsᴛᴀɴᴄᴇ ᴏғ ʜɪs sᴄʜᴏᴏʟ ғʀᴏᴍ ʜɪs ʜᴏᴜsᴇ.


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Answer 1

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Let the distance of his school from the house be x.

⇉The difference time =

$(15 - 5)min \\ = 10 \: min \\ = \frac{10}{60}hr \\ = \frac{1}{6} hr$

⇉Speed during next journey = 10 + 2 = 12 km/hr.

➤ According to the question,

$\frac{x}{10} - \frac{x}{12} = \frac{1}{6} \\ = \frac{x}{5} - \frac{x}{6} = \frac{1}{3} \\ = \frac{6x - 5x}{30} = \frac{1}{3} \\ = \frac{x}{30} = \frac{1}{3} \\ x = \frac{30}{3} \\ x = 10 \: km$

∴ The distance of boy school from house is 10km.

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Answer 2

Let the distance of his school from the house be x.

= the difference time = (15-5)min

= 10 min

=10/60 hours

= 1/6 hours

= Speed during next journey = 10+2=12km/hr.

☞According to the ques.

x/10-x/12 = 1/6

= x/5 - x/6 = 1/3

=6x-5x/30 = 1/3

= x/30 = 1/3

= x = 30/3

= x = 10 km

☞ the distance of boy school from house is 10km.

Sorry for give late answer ..coz my net was slow..

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