Question

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Answer 1

Explanation:

emf of cells when connected in series is

nE

and when connected in parallel is (e/r1 + e/r2) / (1/r1 + 1/r2)

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Answer 2

Explanation:

We have two cells E1 and E2 with internal resistance r1 and r2 connected in parallel with a resistor R.

Let, I1 and I2 be the current through E1 and E2 respectively.

By applying KCL(Kirchhoff's Current Law),

I = I1 + I2

Let there resultant EMF is Eeff and resultant resistance be Req.

By KVL(Kirchhoff's Voltage Law)

Potential across R = Eeff - I*Req

Potential across upper branch = E1 - I*r1

Potential across Lower Branch = E2 - I*r2

After solving we will get

Eeff = (E1/r1 + E2/r2)*Req

and

Req = r1*r2/(r1 +r2)

Eequa=(E1R2+E2R2)/(R1+R2)

hope it's help...

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