Question

$\sf{Help..!}$ ​

Answer 1

Answer:

i hope this is correct.....

this is the value of q^2

i forgot to write their square

so q = 8 * 10^(-6)

and that is 10^(-12)

Answer 2

$\bold {\huge {Your ~answer :-}}$

$\huge {\boxed {\bold {\color {red} {8\:μC}}}}$

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Given—

distance b/w charged particles (r) =18cm = 18× 10¯² m

q1=q2

Potential energy(U) = 3.2 J

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We know

$\huge U = \frac{kq1q2}{r}$

Substitute the value

=> 3.2 = (9 × 10^9 q× q) /(18× 10¯²)

=> q² = (3.2× 18 × 10¯²)/(9×10^9)

Taking root both side

=> q = 8 × 10^¯6 C

=> q= 8 μC

Therefore, Charge on each particle is 8 μC

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Short Note—

1. $\huge U = \frac{kq1q2}{r}$
2. 1 μC = 1 × 10^¯6 C
3. k = 9 × 10 ^9

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$\huge{\red{\ddot{\smile}}}$