Question

$\sf{if \: a = 3 \: and \: d = 4}$
$\sf{find \: t_n \: and \: t_{10}}$
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Answer 1

Answer:

G00D mörñîñg...

n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)

Given n(A)=7

n(B)=9

n(A∪B)=14

Substituting in 1

1=7+9−n(A∩B)

⇒n(A∩B)=16−14=2

hope it helps you.(◍•ᴗ•◍)❤

Answer 2

Given :-

• a = 3
• d = 4 .

To Find :-

• T(n) = ?
• T(10) = ?

Solution :-

we know that, nth term of an AP is ,

• T(n) = a + (n - 1)d where a is first term and d is common difference .

so,

→ T(n) = a + (n - 1)d

→ T(n) = 3 + (n - 1)4

→ T(n) = 3 + 4n - 4

→ T(n) = (4n - 1) .

and,

→ T(10) = a + (10 - 1)d

→ T(10) = 3 + 9 * 4

→ T(10) = 3 + 36

→ T(10) = 39 .

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