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  \sf{If   \: \alpha  \:  and \:   \beta   \: be \:  two \:  zeros  \: of  \: the  \: quadratic \:  polynomial} \\  \sf{ax ^{2}  + bx + c, then  \: evaluate :  }\\  \\ \sf{(i) \: \alpha^{2} + \beta^{2} }\\ \\ \sf(ii) \: \alpha^{3} + \beta^{3} \\ \\ \sf(iii) \: \frac{1}{ \alpha^{3} }

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Answered by itzheartcracker13
21

question:

\sf{If \: \alpha \: and \: \beta \: be \: two \: zeros \: of \: the \: quadratic \: polynomial} \\ \sf{ax ^{2} + bx + c, then \: evaluate : }\\ \\ \sf{(i) \: \alpha^{2} + \beta^{2} }\\ \\ \sf(ii) \: \alpha^{3} + \beta^{3} \\ \\ \sf(iii) \: \frac{1}{ \alpha^{3} }</p><p>

Answer:

we are given with Quadratic polynomial , f(x) = ax² + bx + c and α & β are zeroes.

We use the relation of coefficient and zeroes.i.e.,

\alpha+\beta=\frac{-b}{a}

\alpha\,\beta=\frac{c}{a}

Consider,

\frac{1}{\alpha^3}+\frac{1}{\beta^3}α31+β31</p><p>[tex]\implies\frac{\alpha^3+\beta^3}{(\alpha\,\beta)^3}

\implies\frac{( \alpha+\beta)^3+3\alpha\,\beta(\alpha+\beta)}{(\alpha\,\beta)^3}

\implies\frac{(\frac{-b}{a})^3+3\frac{c}{a}(\frac{-b}{a})}{(\frac{c}{a})^3}

\implies\frac{\frac{-b^3+3abc}{a^3}}{\frac{c^3}{a^3}}

\implies\frac{-b^3+3abc}{c^3}

\implies\frac{3abc-b^3}{c^3}

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