Answers
Given polynomial is p(x) = x³ + x² – 4x – 4
x – 2 is its factor, if p(2) = 0
p(2) = (2)3 + (2)2 – 4(2) – 4 = 8 + 4 – 8 – 4 = 0
Thus, x – 2 is a factor of p(x).
Now, x³ + x²– 4x + 4 = x²(x + 1) – 4(x + 1)
= (x + 1) (x² – 4)
= (x + 1) (x + 2) (x – 2)
Hence, the required factors are (x + 1), (x + 2) and
(x – 2).
Question
If x² - 4 is a factor of polynomial x³ + x² - 4x - 4, then its factors are :-
Answer
The required factors of given polynomial, take
Concept
Given that, x² - 4 is a factor of the given polynomial f(x) = x³ + x² - 4x - 4. Let's write the factor in the simplified form first. x² - 4 = 0 ; this implies that (x+2)(x-2) is a factor of f(x) by Remainder and Factor Theorem's principle but it's not the only factor to find the other factors too we apply the basic sense that if a times b gives the product c then along with a , b will also be the factor of c. Similarly, if (x+2)(x-2) is a factor of f(x) then Let's find the one more factor multiplied to which it bears the exact polynomial.
Calculation of third factor
Thus, other then (x+2) we got one more factor i.e x² - x - 2 = (x-2)(x+1) since we know (x-2) as a factor what new factor we get is (x+1) therefore
Factor of f(x) = (x+2)(x-2)(x+1)
Remainder Theorem
Remainder Theorem states that if f(x) a polynomial is divided by x-a then the remainder would be f(a).
Factor Theorem
Factor Theorem states that if f(a) is a remainder of polynomial f(x) which bears a remainder 0 then this means that (x-a) is a factor of that polynomial.