Question

$\sf\large\underline\purple{Question:-}$
kinetic energy of an object of mass, m moving with a velocity of 5 ms 1 is 25 What will be its kinetic energy when its velocity is doubled? What will be its kine energy when its velocity is increased three times.​

Answer 1

Given :-

• Kinetic energy of the object = 25 J
• Velocity of the object = 5 m/s

To Find :-

• K.E required when velocity is doubled = ?
• K.K required when velocity increased 3 times = ?

Solution :-

• To calculate the K.E when the velocity is doubled and increased 3 times at first we have to calculate the mass of the object by applying formula. Then calculate K.E when the velocity is doubled and 3 times increased.

Formula Used :-

⇢ K.E = 1/2 × m × v²

• K.E = Kinetic energy
• m = mass of object
• v = velocity of object

⇢ 25 = 1/2 × m × 5²

⇢ 25 = 25m/2

⇢ 25m = 50

⇢ m = 2 kg

• Now calculate K.E when velocity is doubled

⇢ K.E = 1/2 × m × v²

• m = 2kg v = 5 × 2 = 10m/s

⇢ K.E = 1/2 × 2 × 10²

⇢ K.E = 1/2 × 2 × 100

⇢ K.E = 100 J

• Now calculate K.E when velocity increased 3 times

⇢ K.E = 1/2 × m × v²

• m = 2kg. v = 5 × 3 = 15m/s

⇢ K.E = 1/2 × 2 × 15²

⇢ k.E = 1/2 × 2 × 225

⇢ K.E = 225 J

Answer 2

Answer:

$\sf\tt\large{\green {\underline {\underline{⚘\;Question:}}}}$

Kinetic energy of an object of mass m moving with a velocity of 5 ms^-1 is 25.What will be its kinetic energy when its velocity is doubled. What will be its kinetic energy when its velocity is increased three times.

$\sf\tt\large{\green {\underline {\underline{⚘\;Answer:}}}}$

(i) The kinetic energy when its velocity is doubled (K.E) = 100 Joule.

(ii) The kinetic energy when its velocity is increased by three times (K.E) =225 Joule .

$\sf\tt\large{\red {\underline {\underline{⚘\;Solution:}}}}$

Hey mate,

First let verify your questions and next enter to calculations.

In the question given that the kinetic energy of an object of mass m moving with a velocity of 5m/s^-1 in 25.

Then we should calculate,

(i) What will be the kinetic energy when its velocity is doubled.

(ii)What will be the kinetic energy when its velocity is increased by three times.

So,

Here we use the formula of kinetic energy to get the perfect answer to your questions.

Formula is ,

$\sf\tt\large{\blue {\underline {\underline{\;K.E \;= \; 1/2 \;× \;mv^2:}}}}$

So,

Consider ,

First let calculate the kinetic energy when its velocity is doubled.

But,

Here we dont know the value of mass So,

By applying the formula of kinetic energy we get the value of mass first let calculate it.

Kinetic energy =1/2 × mv^2

Kinetic energy =1/2 × m × 5^2.

25 = 25 m× 1/2

25 ×2 = 25m

50 = 25m

50/25 = m

2 = m

Therefore ,

Mass= 2kg.

Apply this mass value and velocity and kinetic energy to get the kinetic energy when its velocity is doubled.

We get,

(i) K.E = 1/2 × mv^2

(i) K.E= 1/2× 2 × 10^2

( here v=10m/s because, according to the given question

v=5×2=10m/s)

(i) K.E = 100 Joule.(Answer)

Now,

(ii)K.E = 1/2 × mv^2

(ii)K.E = 1/2 × 2 × 15^2

(Here v=15m/s because according to the given question v =5×3 = 15m/s.)

(ii)K.E = 225Joules .(Answer)

Hence,

This is the perfect answer to your question.

Hope it helps u mate.

Thank you .