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Step-by-step explanation:
log a-logb = log(a/b)
so
remove log on both sides
(x^2+15a^2)/(a-2)= 8ax/(a-2)
(x^2+15a^2)=8ax
so 9 is the one of the roots
so
81+15a^2=8*9a
15a^2-72a+81=0
5a^2-24a+27=0
5a^2-15a-9a+27=0
5a(a-3)-9(a-3)=0
(a-3)(5a-9)=0
a=3 or 5a=9
a=9/5
put these values in the above equation and find other root
if we take 9/5 we will get negative in the place of a-2 so
a=3
so equation will be x^2+15*9=8*3*x
x^2-24x+135=0
so sum of the zeros =(-b/a)= 24
9+β=24
β=24-9
β=15
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Answer:
Let X,Y and Z be three jointly continuous random variables with joint PDF
fXYZ(x,y,z)=⎧⎩⎨⎪⎪13(x+2y+3z)00≤x,y,z≤1otherwise
Find the joint PDF of X and Y, fXY(x,y)
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