Question

$\sf\pink{ \dag}Any \: moderators$

$\rm \: What \: sum \: of \: money \: \\ \rm lent \: out \: at \: 10 \\ \rm \: percent \: p.a. \: simple \: \: interest \\ \rm would \: produce \: ₹ 8500 \: as \: interest \\\rm in \: 2 \: years?$
•Solve this .
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Answer 1

Here is your answer Eline!

Hope it helps ❄️

Answer 2

Step-by-step explanation:

example=

Given

P=Rs.8500,n=2 yrs

We know that amount A at the end of n years at the rate R % per annum when the interest is compounded annually is

A=P(1+ 100R ) n

=8500(1+ 100) 2

=8500( 100106 ) 2 = 10085×106 2

=0.85×106 2

=Rs. 9550.6

Also CI=A−P=9550.6−8500.0=Rs1050.6

We know that SI= 100PRT

= 1008500×6×2

=Rs1020

∴ Difference between CI and SI

CI−SI=9550.6−1020.0=Rs.8530.6

______________

liven SI = 8500

Rate = 10%

Time = 2 2 years

Let principal be P New, s1 = PXRXT 100

8500 = PX 10 X 2 100

= P = 8500 x 100 50

=> P = = 42500