Question

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The attached figure shows a sector OAP of a circle with centre O, containing ∠$\theta$. AB is the perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is :-

$\sf \purple{ r \bigg[\tan \theta + \sec \theta + \dfrac{ \pi \theta}{180} - 1 \bigg]}$
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Answer 1

Answer:

The attached figure shows a sector OAP of a circle with centre O, containing ∠\thetaθ . AB is the perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is :-

\sf \purple{ r \bigg[\tan \theta + \sec \theta + \dfrac{ \pi \theta}{180} - 1 \bigg]}r[tanθ+secθ+

180

Answer 2

Answer:

ok wait

i am giving

pls u also give me..