Math, asked by Anonymous, 11 days ago


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❍Hameed has built a cubical water tank with lid for his house, with each outer edge 1.5 m long. He gets the outer surface of the tank excluding the base, covered with square tiles of side 25 cm (see in the figure below). Find how much he would spend on the tiles if the cost of the tiles is Rs.360 per dozen.

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Answers

Answered by Itzheartcracer
2

Given :-

Hameed has built a cubical water tank with a lid for his house, with each outer edge 1.5 m long. He gets the outer surface of the tank excluding the base, covered with square tiles of side 25 cm (see in the figure below).

To Find :-

Find how much he would spend on the tiles if the cost of the tiles is Rs.360 per dozen.

Solution :-

We know that

1 m = 100 cm

1.5 m = 100 + 50 = 150 cm

It is given in the question that it is excluding base

So total edge to be tiled = 5

Surface area = 5a²

Surface area = 5(150)

Surface area = 112500 cm²

Now

Area of tile = side²

Area of tile = (25)²

Area of tile = 625 cm²

Total tile required = Surface area of house/Area of tile

Total tile required = 112500/625

Total tile required = 180

Cost of dozen tiles = 360

Cost of 1 tile = 360/12

Cost of 1 tile = Rs. 30

Cost of 180 tiles = 180 × 30

Cost of 180 tiles = 5400

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