Question

$\sf\red{ \: easy \: question ↓}$
★A wall 9 m long,6 m high and 20 cm thick, is to be construed, using bricks of dimensions 30 m, 15 cm and 10 cm. How many bricks will be required?

$\sf{no. \: of \: bricks = \frac{volume \: of \: wall}{volume \: of \: one \: brick} }$
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★ question should Must be explain..!​

Answer 1

Answer:

Given that,

Both the wall and the brick are of the shape of cuboid .

l=9m , b=20cm = 0.2m , h=6m

Volume of cuboid = l×b×h

$= 9 \times 0.2 \times 6 \\ \\ \boxed{ = {10.8m}^{3} }$

$\implies \: 10.8 \times {10}^{6} {cm}^{3} = 10800000 {cm}^{3}$

Volume of each brick=

$30 \times 15 \times 10= {4500cm}^{3}$

$\sf{\star \: no. \: of \: bricks = \frac{volume \: of \: wall}{volume \: of \: one \: brick} }$

$= \frac{10800000}{4500} \\ \\ \boxed{\implies \: 2400}$

$\rule{200pt}{2.5pt}$

Answer 2

Answer:

Given that,

Both the wall and the brick are of the shape of cuboid .

l=9m , b=20cm = 0.2m , h=6m

Volume of cuboid = l×b×h

= 9 × 0.2 x 6

= 10.8m³

= 10.8 x 106 cm³

= 10800000cm³

Volume of each brick

= 30 x 15 x 10

= 4500cm³

= no. of bricks

$\frac{ \:volume \: of \: wall}{volume \: of \: one \: brick}$

{10800000}/{4500}

= 2400