Question

$\sf{ \red{Hey \ Everyone....!}}$
Answer this maths question
[Chapter Trigonometry, Class 10]
Prove that:-

$\bf( \dfrac{1}{ {sec}^{2} \alpha - {cos}^{2} \alpha } + \dfrac{1}{ {cosec}^{2} \alpha - {sin}^{2} \alpha})(sec2α−cos2α1​+cosec2α−sin2α1​) \ \textless \ br /\ \textgreater \ \bf\times {sin}^{2} \alpha \ {cos}^{2} \alpha =×sin2α cos2α= \ \textless \ br /\ \textgreater \ \sf{ \purple{\dfrac{1 - {sin}^{2} \alpha \ {cos}^{2} \alpha }{ 2 + {sin}^{2} \alpha \ {cos}^{2} \alpha }}}2+sin2α cos2α1−sin2α cos2α​$
[Note that it has × sign also in LHS, and it is continued. Both LHS and RHS are written in different fonts]

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Answer 1

Answer:

plz refer to the attached pic for the answer

• force is an act of push or pull

sorry sis

not understood ur question properly

I tried but not got

so I attached this pic

hope it helps u a little

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Answer 2

Solution;^

Hru akka..

sry for copy paste..

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