Question

$\sf \red{Question:}$
Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm×20cm×5cm and the smaller of dimension 15cm×12cm×5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm², find the cost of cardboard required for supplying 250 boxes of each kind.

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Answer 1

Total S.A of bigger box

=2(lb+bh+lh)

=2(25×20+25×5+20×5) cm 2

=2(500+125+100)

=1450 cm 2

⇒For overlapping extra area required =

100

450×5

=72.5 cm 2

∴ Total S.A (including overlaps)

=1450+72.5=1522.5 cm 2

Area of cardboard sheet for 250 such boxes

=(1522.5×250) cm 2

Total S.A of smaller box

=2(15×12+15×5+12×5)cm 2

=630 cm 2

For overlapping area required =

100

630×5

=31.5 cm 2

Total S.A (including overlaps)=630+31.5=661.5 cm 2

Area of cardboard sheet required for 250 such boxes

=250×661.5cm 2

=165375 cm 2

Total cardboard sheet required =380625+165375

=54000 cm 2

⇒Cost of 1000 cm 2

cardboard sheet = Rs.4

⇒Cost of 546000 cm 2

cardboard sheet

= Rs.

1000

546000×4

= Rs. 2184

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Answer 2

Answer:

rs.2184

Step-by-step explanation:

Total S.A of bigger box = 2(lb + bh+lh)

= 2(25 x 20 +25 × 5 + 20 × 5) cm²

= 2(500 + 125 + 100)

= 1450 cm²

⇒For overlapping extra area required

450 × 5

100

... Total S.A (including overlaps)

= 1450 + 72.5 1522.5 cm²

Area of cardboard sheet for 250 such boxes (1522.5 x 250) cm²

Total S.A of smaller box

= 2(15 x 12+ 15 x 5 + 12 x 5)cm²

= 630 cm²

For overlapping area required

630 × 5

100

Total S.A (including overlaps)

=

630 +31.5 661.5 cm²

= 31.5 cm²

= 72.5 cm²

Area of cardboard sheet required for 250 such

boxes

= 250 x 661.5cm² 165375 cm²

Total cardboard sheet required = 380625 + 165375 54000 cm²

⇒Cost of 1000 cm² cardboard sheet = Rs.4

⇒Cost of 546000 cm² cardboard sheet

546000 × 4

1000

= Rs.

Rs. 2184

hope it help's you