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Answered by
4
Answer:
(2.3)3−0.027 =(0.23)2+2.3×0.3+(0.3)2(2.3)3−(0.3)3
We know, a3−b3=(a−b)(a2+ab+b2)
=(0.23)2+2.3×0.3+(0.3)2(2.3−0.3)[(2.3)2+2.3×0.3+(0.3)2]
=(2.3−0.3)
=2
Answered by
6
Answer:
(2.3)3−0.027 =(0.23)2+2.3×0.3+(0.3)2(2.3)3−(0.3)3
We know, a3−b3=(a−b)(a2+ab+b2)
=(0.23)2+2.3×0.3+(0.3)2(2.3−0.3)[(2.3)2+2.3×0.3+(0.3)2]
=(2.3−0.3)
=2
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