Math, asked by Anonymous, 10 months ago

\sf{ Sin^{-1} \: 2x \: \frac{d}{dx} \sqrt{1 - x^2} + \sqrt{1 - x^2} \frac{d}{dx} Sin^{-1} \: 2x}

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Answered by Anonymous
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Refer to the attached image

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Answered by simran7539
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see the attachment...

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