Question

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Answer 1

Given :

• Sanket purchased a rectangular plot having area 200 m².

• Length of the plot was 10 m more than its breadth

To find :

• Length and the breadth of the plot .

Hint :

• Let the breadth of the plot be x metre .

Solution :

Length = ( x + 10 ) metre .

Area of rectangle = length x breadth .

200 = (x + 10) x

200 = x² + 10 x

That is x² + 10x = 200

x² + 10x - 200 = 0

Now, solving equation x² + 10x - 200 = 0 .

Answer 2

$\huge\sf\underline\red{Question}$

• Sanket purchased a rectangular plot having area 200 m square .length of the plot was 10m more than its breadth. find the length and breadth of the plot

$\huge\sf\underline\red{Answer}$

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According to the question,

area of the rectangular plot = 200 sqm.

⟼i.e. L x B = 200 sqm.

As per condition, L = B + 10.

Putting the value of L we get,

(B + 10) x B = 200 sqm.

or, B²+10B = 200

or, B²+10B - 200 = 0

or, B²+10B + 20B - 10B - 200 = 0

or, B(B + 20) - 10(B + 20) = 0.

or, (B - 10) (B + 20) = 0

Since breadth cannot be negative so, B = 10m.

Therefore,

L = B + 10 = 10 + 10 = 20m (Ans)

$\small\fbox\pink{Thus\:length = 20m,\:breadth = 10m}$

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