Question

$\sf solve \: for \: 'x' \: \sqrt{3} {x}^{2} \: - \: \sqrt{2} x \: + \: 3\sqrt{3} \: = \: 0$​

Answer 1

Answer:

your answer is here nandu...

in the given expression,

a = √3 ; b = -√2 ; c = 3√3

we know that,

D (discriminant) = b² - 4ac

= 2 - 4 × √3 × 3√3

= 2 - 36

D = - 34

now,

x = - b +/- √D

2a

(note - +/- is mean by + or - )

x = √2 +/- √34

2√3

x = √2 + √34 ; x = √2 - √34

2√3 2√3

hope this will help you nandu....

hope this will help you nandu....press heart ♥️♥️ if my answer touches your heart ♥️ ♥️....

mark as brainlist if you really understood the concept...

if not then, I will explain clearly...

THANK YOU......!!!