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ashamonikakati2:
hi
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Answered by
2
We have [H3O+]=10−pH=10−6.99=1.02⋅10−7 and [OH−]=10−pOH=10−7.01=9.77⋅10−8.
Because of H3O++OH−⟶2H2O we are left with [H3O+]=1.02⋅10−7−9.77⋅10−8=4.6⋅10−9
Answered by
4
4.6.9.4 is the answer guys
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