Question

$show \: \: \: \: \: that \: \: \: \: \: \cos \: \: theta \div 1 + \sin(theta) \: + \: 1 + \sin(theta) \div \cos(theta \:) = 2 \sec(theta) \\ \\ answer \: this \: plz$
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Answer 1

$\frac{cos \theta}{1 + sin \theta} + \frac{1 + sin \theta}{cos \theta} \\ = \frac{ {cos}^{2} \theta + ( {1 + sin \theta})^{2} }{cos \theta(1 + sin \theta)} \\ = \frac{ {cos}^{2} \theta + 1 + {sin}^{2} \theta + 2sin \theta }{cos \theta(1 + sin \theta)} \\ = \frac{2 + 2sin \theta}{cos \theta(1 + sin \theta)} \\ = \frac{2}{cos \theta} \\ = 2sec \theta$

Answer 2

Answer:

l don't understand this