Math, asked by JatinRawat288, 2 months ago


show \: that \: the \: polynomials \: given \: below \: have \: no \: real \: zeroes: \\ (i)x^{2}  - 2x + 5 \:  \:  \: (ii) x^{2} + 6x + 10

Answers

Answered by skkrt
1

Answer:

Let's give x=1

Step-by-step explanation:

P(1)= 1²-2×1+5

= 1-2+5=6-2

=4

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