Question

$sin( 0) = \frac{4}{5} \cos(0) = x.$
find the value of x. ​

Answer 1

Answer:-

$cosθ= \frac{3}{5}$

Explaination:-

Given:-

$sinθ= \frac{4}{5}$

we know the trigonometry identity:

$\boxed {cos^{2}\theta=1-sin^{2}\theta } </u><u>[</u><u>\</u><u>t</u><u>e</u><u>x</u><u>]</u></p><p></p><p></p><p></p><h3><u>N</u><u>o</u><u>w</u><u>,</u></h3><p></p><p><u>[tex]cos {}^{2} θ=1− (\frac{4}{5} ) {}^{2} \\ \\ =1− \frac{16}{25} \\ \\ = \frac{25 - 16}{25 } \\ \\ = \frac{9}{25}$

$⟹cosθ= \sqrt{ \frac{9}{25} } \\ \: \: \: \: = \frac{3}{5}$

Therefore,

$cosθ= \frac{3}{5}$