please answer it
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HERE IS YOUR ANSWER
Step-by-step explanation:
We know that sin-1 x is defined for x ∈ [-1,1]
∴ f(x) = sin-1 √(x-1) is defined if
⇒ 0 ≤ √(x-1)≤ 1
⇒ 0 ≤ x - 1 ≤ 1 [∵√(x-1 ≥ 0 and -1 ≤ √(x-1 ≤ 1]
⇒ 1 ≤ x ≤ 2
∴ x ∈ [1,2]
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