Question

$\sin^{2} 45 - \sin ^{2} 15 = \sqrt{3 \div } \: 4$
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Answer 1

l do not know how I solve

Step-by-step explanation:

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Answer 2

Sin (15°) = Sin (45°— 30°)

Now according to the formula

Sin(A— B) = sinAcosB — cosAsinB (HERE A AND B ARE TWO DIFFERENT ANGLES)

So by applying it you get

Sin (15°) = sin(45°)cos(30) — cos(45°)sin(30°)

= 1/root 2 × root3/2 — 1/root2 × 1/2

= root3/2 root2 — 1/2 root2

= root3 — 1/ 2 root2

So by squaring this

We get

4– 2 root3/ 8

Now put the values in the formula

Cos^2 (45°) — sin^2(15°)

= 1/2 — ( 1/2 — root3/4)

= root3/4

Cheers

Step-by-step explanation:

this is your answer