Question

${sin}^{2}(51 - x) + {sin}^{2} (39 + x) =$
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Answer 1

Answer:

sin²(51-x)+sin²(39+x)

=sin(51)+sin(39+0)

=0.670229+sin(39+0)

=0.670229+sin(39)

=0.670229+0.963795

=1.634025

Answer 2

Hii

you are welcome in my and

sin^2(51- X ) + sin^2 (39+X)

sin^2 (51 - X) + sin^2(90 - (51 -x))

sin^2 (51 - X) + cos^2(51 - X)

1

since

sin^2A + cis^2B = 1

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Hope it may helps you✊✌️