Math, asked by abhishekyadava930, 6 months ago

$\sin( 2\alpha )$

Answers

Answered by suguhaneesh05

1

Δ=∣∣∣∣∣∣cos2α−sin3αsin2αcos3α∣∣∣∣∣∣

=cos2αcos3α+sin3αsin2α

=cos(2α−3α)

=cos(−α)

=cosα

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