Math, asked by shaileshdev121, 10 months ago


 {sin}^{2} +  {cos}^{2}

Answers

Answered by jaswanthsunkara17
0

Answer:

1

Step-by-step explanation:

Consider a right angled triangle ABC right angled at B

Then sin=opp/hypotenuse and cos=adj/hypotenuse

then sin=a/c and cos=b/c

Now, substituting in the given equation

we get,

(a/c)^{2} +(b/c)^{2}\\

Now by pythagoras theorem we know that a^{2}+b^{2}=c^{2}

then we get,

\frac{c^{2} }{c^{2} }

which is equal to 1

Therefore sin^{2}x+cos^{2}x=1

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