Question

${ \sin }^{2} \frac{\pi}{6} + { \cos}^{2} \frac{\pi}{4} + { \tan }^{2} \frac{\pi}{3} + { \cot }^{2} \frac{\pi}{6} = \frac{27}{4}$
Proved it. ​

Answer 1

Step-by-step explanation:

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