Question

${sin}^{3} \alpha - {cos }^{3} \alpha =$
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Answer 1

Answer:

note : i will use beta in place of alpha.

sin ³ß - cos³ß

= (sinß - cosß)(sin²ß + cos²ß + sinßcosß)

= ( sinß - cosß)( 1 + sinßcosß). ( using , sin² ß + cos²ß = 1).

Answer 2

Answer:

According to question:-

${sin}^{3} \alpha - {cos}^{3} \beta$

$= ( {sin}^{2} \alpha - {cos}^{2} \beta )(1 - 2 {sin}^{2} \alpha </strong><strong> </strong><strong> {cos}^{2} \beta</strong><strong>)</strong><strong>$

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