Math, asked by faisal926594, 11 months ago


 \sin(3a)  =
 \cos(3a = )
tan3 a =


RagaviRagavendra: Thanks for following

Answers

Answered by Anonymous
3

1) \:  \:  \sin(3 \alpha )  =  \: 3 \sin( \alpha )  - 4 \sin {}^{3} ( \alpha )  \\  \\  \\  \\ 2) \:  \:  \:  \:  \cos(3 \alpha )  = 4 \cos {}^{3} ( \alpha )  - 3 \cos( \alpha )  \\  \\  \\  \\ \\ 3)  \tan(3 \alpha )  = 3 \tan( \alpha )  - 4 \tan {}^{3} ( \alpha )  \div (1 - 3 \tan {}^{2} ( \alpha )

Answered by aritrimandal
0
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