Question

$sin \: 67°12'$
The value of this is 0.9219
explain me how it is ?
give step by step explanation.
please Don't give me other answers..​

Answer 1

Answer:

please mark me as brainlest

Step-by-step explanation:

We could use the half-angle identity:

sin

(12x)=±√1−cosx2

Explanation:

67.52=12(135∘) (Multiply 67.5×2 .)

The formula doesn't tell us whether

sin

67.5

∘

is positive or negative, but, since it is an acute angle we know that the sine is positive. (Be careful of the difference between "sign" and "sine").

We also need

cos

135

∘

. (That is the special angle that is

45

∘

in Quadrant II.)

cos

135∘=−√22 .

Now use the formula ans simplify:

sin

67.5∘=

sin(12(135∘))=√1−cos135∘2⎷1−

(−√22)2=⎷1+√22=

√2+√24=√2+√22

sin

67.5∘=√2+√22

Answer 2

Answer:

hii

Step-by-step explanation:

thanks for answer myself Sneh from UP