Question

$(Sin A + cos A)^2 - 2sinA . cosA$ is equal to :
(A) 0
(B) 2
(C) 1
(D) $Sin^2 A - cos^2 A$

Answer 1

Hey mate here is your answer
Hope it helps you
Thank you

Answer 2

HELLO DEAR,

we know:- (a + b)² = a² + b² + 2ab

(Sin²A + Cos²A = 1)

So, (sinA + cosA)² - 2sinA . cosA

=> sin²A + cos²A + 2sinA . cosA - 2sinA . cosA

=> (sin²A + cos²A) $\bold{\sf{\cancel{+2sinA.cosA} - \cancel{2sinA.cosA}}}$

=> 1

Hence, option (c) is correct

I HOPE IT'S HELP YOU DEAR,

THANKS