Question

$sin \: a \: tan \: a \div 1 - cos \: a = 1 + sec \: a$
pls soleve
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Answer 1

LHS = sinᎾtanᎾ/1-cosᎾ

sin Ꮎ• sinᎾ/cosᎾ

1 - cosᎾ

sin²Ꮎ

cosᎾ(1-cosᎾ)

(1 - cos Ꮎ) (1 + cos Ꮎ)

cosᎾ (1 cosᎾ )

1 + cos Ꮎ = 1 = cosᎾ

cosᎾ cosᎾ cosᎾ

= secᎾ + 1

= RHS

Hence proved✅