Question

$\sin( \alpha ) + \cos( \alpha ) = \tan( \alpha )$
prove that​

Answer 1

Step-by-step explanation:

let the perpendicular, base, height be p, b, h respectively

sin a = p/h

cos a = b/h

actually tan a = sin a /cos a

hence it cant be proved that sin a + cos a = tan a

tan a = p/h

whereas on adding, it will be (p+b)/h