Question

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$\sin(\pi \cos( \alpha ) ) = \cos(\pi \sin( \alpha ) ) \\ \\ then \: \: \: sin2 \alpha$
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Answer 1

Sorry, I can't get your question

Answer 2

$\sin( \pi \cos( \alpha ) ) = \cos(\pi \sin( \alpha ) )$

$\sin(\pi\ \cos( \alpha ) ) = \sin(\pi \div 2 - \pi \sin( \alpha ) )$

$\pi \cos( \alpha ) = { \sin}^{ - 1} \sin(\pi \div 2 - \pi \sin( \alpha ) )$

π(cos a+sin a)=π\2

root 2(cosa +sin a)=1/2

sin(π\4+a)=1/2root2
find value of a then put in sin2a